14x^2+8x=70

Solution for 14x^2+8x=70 equation:

14x^2+8x=70

We move all terms to the left:

14x^2+8x-(70)=0

a = 14; b = 8; c = -70;
Δ = b2-4ac
Δ = 82-4·14·(-70)
Δ = 3984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3984}=\sqrt{16*249}=\sqrt{16}*\sqrt{249}=4\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{249}}{2*14}=\frac{-8-4\sqrt{249}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{249}}{2*14}=\frac{-8+4\sqrt{249}}{28}
$